提交时间:2025-10-18 13:04:52

运行 ID: 38587

#include<bits/stdc++.h> using namespace std; long long n,c,sumx,sumy; int main(){ scanf("%lld%lld",&n,&c); for(int i=1;i<=n;i++){ long long a; scanf("%lld",&a); sumx+=a; } for(int i=1;i<=n;i++){ long long b; scanf("%lld",&b); sumy+=b; } long long T=-sumy+sumx+c*n; long long ans=T/n/2; if((__int128_t)(ans)*(__int128_t)(T)-(__int128_t)(ans)*ans*n<=(__int128_t)(ans+1)*(__int128_t)(T)-(__int128_t)(ans+1)*(ans+1)*n){ ans=ans+1; } printf("%lld %lld",ans,c-ans); return 0; }