#include<bits/stdc++.h> using namespace std; #define int long long int n,ans; signed main(){ ios::sync_with_stdio(0); cin.tie(0),cout.tie(0); cin>>n; for(int i=1;i<=2*n;i*=2){ for(int j=1;j*i<=2*n;j+=2){ if(n+1<=i*j&&i*j<=2*n){ ans+=j; } } } cout<<ans; return 0; } /* 思路： 1：2^k/f(2^k)=1 2：枚举2^k*(p) */